** Permutation and combination - class 12 math .**

Q)In How many ways can a man send three of his children to seven different college of certain town?

** Solution: **

There are 7 colleges and 3 children .

A man has 7 choices for his one child at first .

A man has remaining 6 choices for next child.

A man has 5 choices for his last child.

Total ways = 7 x 6 x 5 = 210 ways.

Hence a man can send three of his children in 210 ways to seven different college of a certain town.

** Thank you**

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