A Horizontal straight wire 5 cm long weighing 1.2 gm-1 is placed perpendicular to a uniform field of flux density 0.6 Tesla. if the resistance of the wire is 3.8 ohm per metre .calculate the potential difference that has to be applied between the ends of wire to make it just self supporting.

Physics numerical class 12 

Q)A Horizontal straight wire 5 cm long weighing 1.2 gm-1 is placed perpendicular to a uniform field of flux density 0.6 Tesla. if the resistance of the wire is 3.8 ohm per metre .calculate the potential difference that has to be applied between the ends of wire to make it just self supporting.

Answer 






Hence , 0.0038 volts of potential  is required to make it just self supporting . 


                                      Thank you 




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